14312224404313 has 4 divisors (see below), whose sum is σ = 15613335713808. Its totient is φ = 13011113094820.

The previous prime is 14312224404307. The next prime is 14312224404343. The reversal of 14312224404313 is 31340442221341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14312224404313 - 2⁴¹ = 12113201148761 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14312224404343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650555654731 + ... + 650555654752.

It is an arithmetic number, because the mean of its divisors is an integer number (3903333928452).

Almost surely, 2^{14312224404313} is an apocalyptic number.

It is an amenable number.

14312224404313 is a deficient number, since it is larger than the sum of its proper divisors (1301111309495).

14312224404313 is a wasteful number, since it uses less digits than its factorization.

14312224404313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1301111309494.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 14312224404313 its reverse (31340442221341), we get a palindrome (45652666625654).

The spelling of 14312224404313 in words is "fourteen trillion, three hundred twelve billion, two hundred twenty-four million, four hundred four thousand, three hundred thirteen".