Base | Representation |
---|---|
bin | 100000100010101101000001… |
… | …110110100000011001000101 |
3 | 200202202100200011120011000010 |
4 | 200202231001312200121011 |
5 | 122224403432300341401 |
6 | 1224221251004140433 |
7 | 42101150005350204 |
oct | 4042550166403105 |
9 | 622670604504003 |
10 | 143122300012101 |
11 | 4166a910191193 |
12 | 14076088837719 |
13 | 61b24b4aa5467 |
14 | 274b228b9d23b |
15 | 1182e15aaaed6 |
hex | 822b41da0645 |
143122300012101 has 8 divisors (see below), whose sum is σ = 190847433952224. Its totient is φ = 95406016373360.
The previous prime is 143122300012079. The next prime is 143122300012147. The reversal of 143122300012101 is 101210003221341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 143122300012101 - 219 = 143122299487813 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143122300012151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2212537611 + ... + 2212602296.
It is an arithmetic number, because the mean of its divisors is an integer number (23855929244028).
Almost surely, 2143122300012101 is an apocalyptic number.
It is an amenable number.
143122300012101 is a deficient number, since it is larger than the sum of its proper divisors (47725133940123).
143122300012101 is a wasteful number, since it uses less digits than its factorization.
143122300012101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4425150691.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 143122300012101 its reverse (101210003221341), we get a palindrome (244332303233442).
The spelling of 143122300012101 in words is "one hundred forty-three trillion, one hundred twenty-two billion, three hundred million, twelve thousand, one hundred one".
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