Base | Representation |
---|---|
bin | 10100110100111011100… |
… | …010011110110000110011 |
3 | 12001211020101120202020020 |
4 | 110310323202132300303 |
5 | 141422121042113321 |
6 | 3013254512014523 |
7 | 205255016544600 |
oct | 24647342366063 |
9 | 5054211522206 |
10 | 1431223004211 |
11 | 501a8408a500 |
12 | 1b1469831443 |
13 | a4c6b4890b0 |
14 | 4d3b32516a7 |
15 | 2736931a4c6 |
hex | 14d3b89ec33 |
1431223004211 has 288 divisors, whose sum is σ = 2791555147584. Its totient is φ = 643778150400.
The previous prime is 1431223004209. The next prime is 1431223004297. The reversal of 1431223004211 is 1124003221341.
It is not a de Polignac number, because 1431223004211 - 21 = 1431223004209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1431223008211) by changing a digit.
It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 2126631171 + ... + 2126631843.
It is an arithmetic number, because the mean of its divisors is an integer number (9692899818).
Almost surely, 21431223004211 is an apocalyptic number.
1431223004211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1431223004211 is a deficient number, since it is larger than the sum of its proper divisors (1360332143373).
1431223004211 is a wasteful number, since it uses less digits than its factorization.
1431223004211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1283 (or 1265 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1431223004211 its reverse (1124003221341), we get a palindrome (2555226225552).
The spelling of 1431223004211 in words is "one trillion, four hundred thirty-one billion, two hundred twenty-three million, four thousand, two hundred eleven".
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