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14312334215121 = 343110948327249
BaseRepresentation
bin1101000001000101100110…
…0110001100011111010001
31212200020122011212000210220
43100101121212030133101
53333443130024340441
650234555013143253
73005013661361655
oct320213146143721
955606564760726
1014312334215121
1146189105a72a8
1217319ab92ab29
137ca8552348a7
14376a1374aa65
1519c46b349466
hexd045998c7d1

14312334215121 has 8 divisors (see below), whose sum is σ = 19526905596000. Its totient is φ = 9319659488832.

The previous prime is 14312334215089. The next prime is 14312334215129. The reversal of 14312334215121 is 12151243321341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14312334215121 - 25 = 14312334215089 is a prime.

It is a super-2 number, since 2×143123342151212 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14312334215129) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55474163496 + ... + 55474163753.

It is an arithmetic number, because the mean of its divisors is an integer number (2440863199500).

Almost surely, 214312334215121 is an apocalyptic number.

It is an amenable number.

14312334215121 is a deficient number, since it is larger than the sum of its proper divisors (5214571380879).

14312334215121 is a wasteful number, since it uses less digits than its factorization.

14312334215121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110948327295.

The product of its digits is 17280, while the sum is 33.

Adding to 14312334215121 its reverse (12151243321341), we get a palindrome (26463577536462).

The spelling of 14312334215121 in words is "fourteen trillion, three hundred twelve billion, three hundred thirty-four million, two hundred fifteen thousand, one hundred twenty-one".

Divisors: 1 3 43 129 110948327249 332844981747 4770778071707 14312334215121