Base | Representation |
---|---|
bin | 11010101010001011… |
… | …00100011010110001 |
3 | 1100221110100112021220 |
4 | 31111011210122301 |
5 | 213302440101022 |
6 | 10324112535253 |
7 | 1014450414663 |
oct | 152505443261 |
9 | 40843315256 |
10 | 14312425137 |
11 | 6084a9992a |
12 | 2935251529 |
13 | 147126a31a |
14 | 99aba2533 |
15 | 58b79885c |
hex | 3551646b1 |
14312425137 has 32 divisors (see below), whose sum is σ = 20843920512. Its totient is φ = 8698881024.
The previous prime is 14312425109. The next prime is 14312425151. The reversal of 14312425137 is 73152421341.
It is not a de Polignac number, because 14312425137 - 216 = 14312359601 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14312425098 and 14312425107.
It is not an unprimeable number, because it can be changed into a prime (14312425037) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 411643 + ... + 445055.
It is an arithmetic number, because the mean of its divisors is an integer number (651372516).
Almost surely, 214312425137 is an apocalyptic number.
14312425137 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
14312425137 is a deficient number, since it is larger than the sum of its proper divisors (6531495375).
14312425137 is a wasteful number, since it uses less digits than its factorization.
14312425137 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33697.
The product of its digits is 20160, while the sum is 33.
Adding to 14312425137 its reverse (73152421341), we get a palindrome (87464846478).
The spelling of 14312425137 in words is "fourteen billion, three hundred twelve million, four hundred twenty-five thousand, one hundred thirty-seven".
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