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1431244211323 = 3298743388129
BaseRepresentation
bin10100110100111100110…
…011011000010001111011
312001211021212111011220211
4110310330303120101323
5141422142004230243
63013300550331551
7205255365032113
oct24647463302173
95054255434824
101431244211323
11501a95054743
121b1474959bb7
13a4c729a2a94
144d3b5db2043
152736b108d9d
hex14d3ccd847b

1431244211323 has 4 divisors (see below), whose sum is σ = 1431287632440. Its totient is φ = 1431200790208.

The previous prime is 1431244211311. The next prime is 1431244211377. The reversal of 1431244211323 is 3231124421341.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1431244211323 - 221 = 1431242114171 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1431224211323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21661078 + ... + 21727051.

It is an arithmetic number, because the mean of its divisors is an integer number (357821908110).

Almost surely, 21431244211323 is an apocalyptic number.

1431244211323 is a deficient number, since it is larger than the sum of its proper divisors (43421117).

1431244211323 is an equidigital number, since it uses as much as digits as its factorization.

1431244211323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43421116.

The product of its digits is 13824, while the sum is 31.

Adding to 1431244211323 its reverse (3231124421341), we get a palindrome (4662368632664).

The spelling of 1431244211323 in words is "one trillion, four hundred thirty-one billion, two hundred forty-four million, two hundred eleven thousand, three hundred twenty-three".

Divisors: 1 32987 43388129 1431244211323