14312443433 has 4 divisors (see below), whose sum is σ = 14555027280. Its totient is φ = 14069859588.

The previous prime is 14312443331. The next prime is 14312443477. The reversal of 14312443433 is 33434421341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14312443433 - 2¹⁴ = 14312427049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14312443433.

It is not an unprimeable number, because it can be changed into a prime (14312443133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121291835 + ... + 121291952.

It is an arithmetic number, because the mean of its divisors is an integer number (3638756820).

Almost surely, 2^14312443433 is an apocalyptic number.

It is an amenable number.

14312443433 is a deficient number, since it is larger than the sum of its proper divisors (242583847).

14312443433 is an equidigital number, since it uses as much as digits as its factorization.

14312443433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 242583846.

The product of its digits is 41472, while the sum is 32.

Adding to 14312443433 its reverse (33434421341), we get a palindrome (47746864774).

The spelling of 14312443433 in words is "fourteen billion, three hundred twelve million, four hundred forty-three thousand, four hundred thirty-three".