143124441540013 has 4 divisors (see below), whose sum is σ = 143135465541408. Its totient is φ = 143113417538620.

The previous prime is 143124441540011. The next prime is 143124441540029. The reversal of 143124441540013 is 310045144421341.

143124441540013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143124441540013 - 2¹ = 143124441540011 is a prime.

It is a super-2 number, since 2×143124441540013² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143124441540011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5511981223 + ... + 5512007188.

It is an arithmetic number, because the mean of its divisors is an integer number (35783866385352).

Almost surely, 2^{143124441540013} is an apocalyptic number.

It is an amenable number.

143124441540013 is a deficient number, since it is larger than the sum of its proper divisors (11024001395).

143124441540013 is a wasteful number, since it uses less digits than its factorization.

143124441540013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11024001394.

The product of its (nonzero) digits is 92160, while the sum is 37.

Adding to 143124441540013 its reverse (310045144421341), we get a palindrome (453169585961354).

The spelling of 143124441540013 in words is "one hundred forty-three trillion, one hundred twenty-four billion, four hundred forty-one million, five hundred forty thousand, thirteen".