Search a number
-
+
143124521111221 = 1320441538602737
BaseRepresentation
bin100000100010101111000110…
…001111010100111010110101
3200202202120101221221200012111
4200202233012033110322311
5122224423004401024341
61224222255230051021
742101256025363636
oct4042570617247265
9622676357850174
10143124521111221
114167084aa118a1
12140765a8649a71
1361b2779cb35b0
14274b399b6d88d
151182ee5a94681
hex822bc63d4eb5

143124521111221 has 8 divisors (see below), whose sum is σ = 154141640382744. Its totient is φ = 132108479086080.

The previous prime is 143124521111207. The next prime is 143124521111233. The reversal of 143124521111221 is 122111125421341.

143124521111221 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 6030162898321 + 137094358212900 = 2455639^2 + 11708730^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143124521111221 - 213 = 143124521103029 is a prime.

It is a super-2 number, since 2×1431245211112212 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143124521111521) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269035636 + ... + 269567101.

It is an arithmetic number, because the mean of its divisors is an integer number (19267705047843).

Almost surely, 2143124521111221 is an apocalyptic number.

It is an amenable number.

143124521111221 is a deficient number, since it is larger than the sum of its proper divisors (11017119271523).

143124521111221 is a wasteful number, since it uses less digits than its factorization.

143124521111221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 538623191.

The product of its digits is 3840, while the sum is 31.

Adding to 143124521111221 its reverse (122111125421341), we get a palindrome (265235646532562).

The spelling of 143124521111221 in words is "one hundred forty-three trillion, one hundred twenty-four billion, five hundred twenty-one million, one hundred eleven thousand, two hundred twenty-one".

Divisors: 1 13 20441 265733 538602737 7001835581 11009578547017 143124521111221