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143126314653 = 372973648399
BaseRepresentation
bin1000010101001011111…
…1100011111010011101
3111200102201102010012210
42011102333203322131
54321110314032103
6145430141351033
713224542413200
oct2052277437235
9450381363183
10143126314653
1155777089663
12238a4868479
131065c4a171a
146cda915937
153aca416e03
hex2152fe3e9d

143126314653 has 12 divisors (see below), whose sum is σ = 221991835200. Its totient is φ = 81786465432.

The previous prime is 143126314603. The next prime is 143126314673. The reversal of 143126314653 is 356413621341.

It is not a de Polignac number, because 143126314653 - 229 = 142589443741 is a prime.

It is a super-2 number, since 2×1431263146532 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143126314603) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 486824053 + ... + 486824346.

It is an arithmetic number, because the mean of its divisors is an integer number (18499319600).

Almost surely, 2143126314653 is an apocalyptic number.

It is an amenable number.

143126314653 is a deficient number, since it is larger than the sum of its proper divisors (78865520547).

143126314653 is an equidigital number, since it uses as much as digits as its factorization.

143126314653 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 973648416 (or 973648409 counting only the distinct ones).

The product of its digits is 155520, while the sum is 39.

Adding to 143126314653 its reverse (356413621341), we get a palindrome (499539935994).

The spelling of 143126314653 in words is "one hundred forty-three billion, one hundred twenty-six million, three hundred fourteen thousand, six hundred fifty-three".

Divisors: 1 3 7 21 49 147 973648399 2920945197 6815538793 20446616379 47708771551 143126314653