1431300014114 has 4 divisors (see below), whose sum is σ = 2146950021174. Its totient is φ = 715650007056.

The previous prime is 1431300014051. The next prime is 1431300014149. The reversal of 1431300014114 is 4114100031341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 771704270089 + 659595744025 = 878467^2 + 812155^2 .

It is a super-4 number, since 4×1431300014114⁴ (a number of 50 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1431300014114.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 357825003527 + ... + 357825003530.

Almost surely, 2^{1431300014114} is an apocalyptic number.

1431300014114 is a deficient number, since it is larger than the sum of its proper divisors (715650007060).

1431300014114 is an equidigital number, since it uses as much as digits as its factorization.

1431300014114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 715650007059.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1431300014114 its reverse (4114100031341), we get a palindrome (5545400045455).

The spelling of 1431300014114 in words is "one trillion, four hundred thirty-one billion, three hundred million, fourteen thousand, one hundred fourteen".