14313002135 has 4 divisors (see below), whose sum is σ = 17175602568. Its totient is φ = 11450401704.

The previous prime is 14313002111. The next prime is 14313002141. The reversal of 14313002135 is 53120031341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14313002135 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14313002135.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1431300209 + ... + 1431300218.

It is an arithmetic number, because the mean of its divisors is an integer number (4293900642).

Almost surely, 2^14313002135 is an apocalyptic number.

14313002135 is a deficient number, since it is larger than the sum of its proper divisors (2862600433).

14313002135 is an equidigital number, since it uses as much as digits as its factorization.

14313002135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2862600432.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 14313002135 its reverse (53120031341), we get a palindrome (67433033476).

The spelling of 14313002135 in words is "fourteen billion, three hundred thirteen million, two thousand, one hundred thirty-five".