143130063521543 has 4 divisors (see below), whose sum is σ = 163577215453200. Its totient is φ = 122682911589888.

The previous prime is 143130063521521. The next prime is 143130063521567. The reversal of 143130063521543 is 345125360031341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143130063521543 - 2⁴⁴ = 125537877477127 is a prime.

It is a super-3 number, since 3×143130063521543³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143130063521543.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143130063521443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10223575965818 + ... + 10223575965831.

It is an arithmetic number, because the mean of its divisors is an integer number (40894303863300).

Almost surely, 2^{143130063521543} is an apocalyptic number.

143130063521543 is a deficient number, since it is larger than the sum of its proper divisors (20447151931657).

143130063521543 is an equidigital number, since it uses as much as digits as its factorization.

143130063521543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20447151931656.

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 143130063521543 in words is "one hundred forty-three trillion, one hundred thirty billion, sixty-three million, five hundred twenty-one thousand, five hundred forty-three".