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14313122311 = 89160821599
BaseRepresentation
bin11010101010010000…
…01110101000000111
31100221111122221122011
431111020032220013
5213303124403221
610324135515051
71014456350365
oct152510165007
940844587564
1014313122311
116085425704
122935528a87
131471452757
1499ad04635
1558b8851e1
hex35520ea07

14313122311 has 4 divisors (see below), whose sum is σ = 14473944000. Its totient is φ = 14152300624.

The previous prime is 14313122267. The next prime is 14313122321. The reversal of 14313122311 is 11322131341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11322131341 = 11633973277.

It is a cyclic number.

It is not a de Polignac number, because 14313122311 - 217 = 14312991239 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14313122321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80410711 + ... + 80410888.

It is an arithmetic number, because the mean of its divisors is an integer number (3618486000).

Almost surely, 214313122311 is an apocalyptic number.

14313122311 is a deficient number, since it is larger than the sum of its proper divisors (160821689).

14313122311 is an equidigital number, since it uses as much as digits as its factorization.

14313122311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 160821688.

The product of its digits is 432, while the sum is 22.

Adding to 14313122311 its reverse (11322131341), we get a palindrome (25635253652).

The spelling of 14313122311 in words is "fourteen billion, three hundred thirteen million, one hundred twenty-two thousand, three hundred eleven".

Divisors: 1 89 160821599 14313122311