Base | Representation |
---|---|
bin | 1000010101001101010… |
… | …1010100110110100011 |
3 | 111200110010010222122210 |
4 | 2011103111110312203 |
5 | 4321113244121011 |
6 | 145430503533203 |
7 | 13224642045222 |
oct | 2052325246643 |
9 | 450403128583 |
10 | 143132020131 |
11 | 5577a326231 |
12 | 238a675a203 |
13 | 1066071b649 |
14 | 6cdb59ccb9 |
15 | 3acab926a6 |
hex | 2153554da3 |
143132020131 has 16 divisors (see below), whose sum is σ = 191050665120. Its totient is φ = 95317416960.
The previous prime is 143132020103. The next prime is 143132020147. The reversal of 143132020131 is 131020231341.
It is not a de Polignac number, because 143132020131 - 29 = 143132019619 is a prime.
It is a super-2 number, since 2×1431320201312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 143132020098 and 143132020107.
It is not an unprimeable number, because it can be changed into a prime (143132420131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16621555 + ... + 16630163.
It is an arithmetic number, because the mean of its divisors is an integer number (11940666570).
Almost surely, 2143132020131 is an apocalyptic number.
143132020131 is a deficient number, since it is larger than the sum of its proper divisors (47918644989).
143132020131 is a wasteful number, since it uses less digits than its factorization.
143132020131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14006.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 143132020131 its reverse (131020231341), we get a palindrome (274152251472).
The spelling of 143132020131 in words is "one hundred forty-three billion, one hundred thirty-two million, twenty thousand, one hundred thirty-one".
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