143132021111101 has 6 divisors (see below), whose sum is σ = 157326932295806. Its totient is φ = 130120019191800.

The previous prime is 143132021111099. The next prime is 143132021111221. The reversal of 143132021111101 is 101111120231341.

It can be written as a sum of positive squares in only one way, i.e., 142875428208601 + 256592902500 = 11953051^2 + 506550^2 .

It is not a de Polignac number, because 143132021111101 - 2¹ = 143132021111099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143132021141101) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 591454632570 + ... + 591454632811.

Almost surely, 2^{143132021111101} is an apocalyptic number.

143132021111101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

143132021111101 is a deficient number, since it is larger than the sum of its proper divisors (14194911184705).

143132021111101 is a wasteful number, since it uses less digits than its factorization.

143132021111101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1182909265403 (or 1182909265392 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 143132021111101 its reverse (101111120231341), we get a palindrome (244243141342442).

The spelling of 143132021111101 in words is "one hundred forty-three trillion, one hundred thirty-two billion, twenty-one million, one hundred eleven thousand, one hundred one".