Base | Representation |
---|---|
bin | 100000100010111001001000… |
… | …111001101110111001100011 |
3 | 200202210121020101100112221002 |
4 | 200202321020321232321203 |
5 | 122230112100104402410 |
6 | 1224231241151422215 |
7 | 42102120150544064 |
oct | 4042711071567143 |
9 | 622717211315832 |
10 | 143135303200355 |
11 | 41675383143a64 |
12 | 140786b752496b |
13 | 61b37a7a223ab |
14 | 274baddb1856b |
15 | 118342743c7a5 |
hex | 822e48e6ee63 |
143135303200355 has 16 divisors (see below), whose sum is σ = 180802782853920. Its totient is φ = 108481316191488.
The previous prime is 143135303200303. The next prime is 143135303200361. The reversal of 143135303200355 is 553002303531341.
It is a cyclic number.
It is not a de Polignac number, because 143135303200355 - 218 = 143135302938211 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 115165319 + ... + 116401551.
It is an arithmetic number, because the mean of its divisors is an integer number (11300173928370).
Almost surely, 2143135303200355 is an apocalyptic number.
143135303200355 is a deficient number, since it is larger than the sum of its proper divisors (37667479653565).
143135303200355 is a wasteful number, since it uses less digits than its factorization.
143135303200355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2455030.
The product of its (nonzero) digits is 243000, while the sum is 38.
Adding to 143135303200355 its reverse (553002303531341), we get a palindrome (696137606731696).
The spelling of 143135303200355 in words is "one hundred forty-three trillion, one hundred thirty-five billion, three hundred three million, two hundred thousand, three hundred fifty-five".
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