Base | Representation |
---|---|
bin | 1101000001001011110101… |
… | …1111101111000100000100 |
3 | 1212200101221222121002021211 |
4 | 3100102331133233010010 |
5 | 3334010043110241312 |
6 | 50235433204221204 |
7 | 3005103342363412 |
oct | 320227537570404 |
9 | 55611858532254 |
10 | 14314010243332 |
11 | 46195a0687088 |
12 | 173219909a804 |
13 | 7caa61539c67 |
14 | 376b321922b2 |
15 | 19c5185653a7 |
hex | d04bd7ef104 |
14314010243332 has 6 divisors (see below), whose sum is σ = 25049517925838. Its totient is φ = 7157005121664.
The previous prime is 14314010243311. The next prime is 14314010243341. The reversal of 14314010243332 is 23334201041341.
14314010243332 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 9167899845316 + 5146110398016 = 3027854^2 + 2268504^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14314010243294 and 14314010243303.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1789251280413 + ... + 1789251280420.
Almost surely, 214314010243332 is an apocalyptic number.
It is an amenable number.
14314010243332 is a deficient number, since it is larger than the sum of its proper divisors (10735507682506).
14314010243332 is a wasteful number, since it uses less digits than its factorization.
14314010243332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3578502560837 (or 3578502560835 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 14314010243332 its reverse (23334201041341), we get a palindrome (37648211284673).
The spelling of 14314010243332 in words is "fourteen trillion, three hundred fourteen billion, ten million, two hundred forty-three thousand, three hundred thirty-two".
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