Search a number
-
+
143140323013202 = 271570161506601
BaseRepresentation
bin100000100010111101110100…
…000110110011001001010010
3200202211002012020000110121102
4200202331310012303021102
5122230202340142410302
61224233431231424402
742102355433341004
oct4042756406631122
9622732166013542
10143140323013202
1141677519753719
1214079678685102
1361b40c79ca158
14274c058696374
15118361cea9702
hex822f741b3252

143140323013202 has 4 divisors (see below), whose sum is σ = 214710484519806. Its totient is φ = 71570161506600.

The previous prime is 143140323013201. The next prime is 143140323013211. The reversal of 143140323013202 is 202310323041341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 91027646987281 + 52112676025921 = 9540841^2 + 7218911^2 .

It is not an unprimeable number, because it can be changed into a prime (143140323013201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35785080753299 + ... + 35785080753302.

Almost surely, 2143140323013202 is an apocalyptic number.

143140323013202 is a deficient number, since it is larger than the sum of its proper divisors (71570161506604).

143140323013202 is an equidigital number, since it uses as much as digits as its factorization.

143140323013202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71570161506603.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 143140323013202 its reverse (202310323041341), we get a palindrome (345450646054543).

The spelling of 143140323013202 in words is "one hundred forty-three trillion, one hundred forty billion, three hundred twenty-three million, thirteen thousand, two hundred two".

Divisors: 1 2 71570161506601 143140323013202