Base | Representation |
---|---|
bin | 1101000001001100001011… |
… | …1010110101011100000101 |
3 | 1212200102012022210212012211 |
4 | 3100103002322311130011 |
5 | 3334010234403432123 |
6 | 50235450214343421 |
7 | 3005105525651542 |
oct | 320230272653405 |
9 | 55612168725184 |
10 | 14314101233413 |
11 | 4619637a842a3 |
12 | 173220365ab71 |
13 | 7caa77347747 |
14 | 376b402b9bc9 |
15 | 19c52153a40d |
hex | d04c2eb5705 |
14314101233413 has 8 divisors (see below), whose sum is σ = 15081649486400. Its totient is φ = 13547970430848.
The previous prime is 14314101233389. The next prime is 14314101233501. The reversal of 14314101233413 is 31433210141341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14314101233413 - 25 = 14314101233381 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14314101033413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 354341868 + ... + 354382261.
It is an arithmetic number, because the mean of its divisors is an integer number (1885206185800).
Almost surely, 214314101233413 is an apocalyptic number.
It is an amenable number.
14314101233413 is a deficient number, since it is larger than the sum of its proper divisors (767548252987).
14314101233413 is a wasteful number, since it uses less digits than its factorization.
14314101233413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 708725211.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 14314101233413 its reverse (31433210141341), we get a palindrome (45747311374754).
The spelling of 14314101233413 in words is "fourteen trillion, three hundred fourteen billion, one hundred one million, two hundred thirty-three thousand, four hundred thirteen".
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