Base | Representation |
---|---|
bin | 1101000001001100100101… |
… | …1101100100110000011111 |
3 | 1212200102110222100202100202 |
4 | 3100103021131210300133 |
5 | 3334011001004102143 |
6 | 50235505135214115 |
7 | 3005111330664662 |
oct | 320231135446037 |
9 | 55612428322322 |
10 | 14314211003423 |
11 | 4619693a39111 |
12 | 173223437733b |
13 | 7caa93ccc206 |
14 | 376b50ad16d9 |
15 | 19c52aebeab8 |
hex | d04c9764c1f |
14314211003423 has 8 divisors (see below), whose sum is σ = 14395297417200. Its totient is φ = 14233137020608.
The previous prime is 14314211003399. The next prime is 14314211003429. The reversal of 14314211003423 is 32430011241341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14314211003423 - 214 = 14314210987039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14314211003429) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 793358 + ... + 5409051.
It is an arithmetic number, because the mean of its divisors is an integer number (1799412177150).
Almost surely, 214314211003423 is an apocalyptic number.
14314211003423 is a deficient number, since it is larger than the sum of its proper divisors (81086413777).
14314211003423 is a wasteful number, since it uses less digits than its factorization.
14314211003423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6215481.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 14314211003423 its reverse (32430011241341), we get a palindrome (46744222244764).
The spelling of 14314211003423 in words is "fourteen trillion, three hundred fourteen billion, two hundred eleven million, three thousand, four hundred twenty-three".
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