Base | Representation |
---|---|
bin | 1000010101001111111… |
… | …1010111101111010011 |
3 | 111200110212212221211021 |
4 | 2011103333113233103 |
5 | 4321124104321003 |
6 | 145431540100311 |
7 | 13225134532033 |
oct | 2052377275723 |
9 | 450425787737 |
10 | 143143042003 |
11 | 55785574115 |
12 | 238aa394697 |
13 | 10662aaa370 |
14 | 6cdcc2b8c3 |
15 | 3acbb1d2bd |
hex | 2153fd7bd3 |
143143042003 has 4 divisors (see below), whose sum is σ = 154154045248. Its totient is φ = 132132038760.
The previous prime is 143143041991. The next prime is 143143042027. The reversal of 143143042003 is 300240341341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 143143042003 - 217 = 143142910931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143143942003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5505501603 + ... + 5505501628.
It is an arithmetic number, because the mean of its divisors is an integer number (38538511312).
Almost surely, 2143143042003 is an apocalyptic number.
143143042003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
143143042003 is a deficient number, since it is larger than the sum of its proper divisors (11011003245).
143143042003 is a wasteful number, since it uses less digits than its factorization.
143143042003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11011003244.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 143143042003 its reverse (300240341341), we get a palindrome (443383383344).
The spelling of 143143042003 in words is "one hundred forty-three billion, one hundred forty-three million, forty-two thousand, three".
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