Base | Representation |
---|---|
bin | 1101000001001100111110… |
… | …1000000111101110101010 |
3 | 1212200102202011222102212122 |
4 | 3100103033220013232222 |
5 | 3334011203443301102 |
6 | 50235523312111242 |
7 | 3005114025055166 |
oct | 320231750075652 |
9 | 55612664872778 |
10 | 14314314431402 |
11 | 4619737361087 |
12 | 1732262b35522 |
13 | 7caaac5730bb |
14 | 376b60735ca6 |
15 | 19c5351000a2 |
hex | d04cfa07baa |
14314314431402 has 4 divisors (see below), whose sum is σ = 21471471647106. Its totient is φ = 7157157215700.
The previous prime is 14314314431401. The next prime is 14314314431449. The reversal of 14314314431402 is 20413441341341.
14314314431402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13053906294361 + 1260408137041 = 3613019^2 + 1122679^2 .
It is not an unprimeable number, because it can be changed into a prime (14314314431401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3578578607849 + ... + 3578578607852.
Almost surely, 214314314431402 is an apocalyptic number.
14314314431402 is a deficient number, since it is larger than the sum of its proper divisors (7157157215704).
14314314431402 is an equidigital number, since it uses as much as digits as its factorization.
14314314431402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7157157215703.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 14314314431402 its reverse (20413441341341), we get a palindrome (34727755772743).
The spelling of 14314314431402 in words is "fourteen trillion, three hundred fourteen billion, three hundred fourteen million, four hundred thirty-one thousand, four hundred two".
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