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14314430323 = 53293921787
BaseRepresentation
bin11010101010011010…
…01101111101110011
31100221121010101220001
431111031031331303
5213303443232243
610324223530431
71014503436004
oct152515157563
940847111801
1014314430323
116086139406
122935a59a17
1314717bcc1b
1499b1651ab
1558ba42a4d
hex35534df73

14314430323 has 8 divisors (see below), whose sum is σ = 14634306288. Its totient is φ = 13996398624.

The previous prime is 14314430293. The next prime is 14314430329. The reversal of 14314430323 is 32303441341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14314430323 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14314430291 and 14314430300.

It is not an unprimeable number, because it can be changed into a prime (14314430329) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 445365 + ... + 476422.

It is an arithmetic number, because the mean of its divisors is an integer number (1829288286).

Almost surely, 214314430323 is an apocalyptic number.

14314430323 is a deficient number, since it is larger than the sum of its proper divisors (319875965).

14314430323 is an equidigital number, since it uses as much as digits as its factorization.

14314430323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 922133.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 14314430323 its reverse (32303441341), we get a palindrome (46617871664).

The spelling of 14314430323 in words is "fourteen billion, three hundred fourteen million, four hundred thirty thousand, three hundred twenty-three".

Divisors: 1 53 293 15529 921787 48854711 270083591 14314430323