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14315142311 = 99257144223
BaseRepresentation
bin11010101010011111…
…11011110010100111
31100221122110120112222
431111033323302213
5213304134023221
610324251102555
71014512462531
oct152517736247
940848416488
1014315142311
116086585328
122936141a5b
1314719ac012
1499b2ac851
1558bb339ab
hex3553fbca7

14315142311 has 4 divisors (see below), whose sum is σ = 14315385792. Its totient is φ = 14314898832.

The previous prime is 14315142301. The next prime is 14315142319. The reversal of 14315142311 is 11324151341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11324151341 = 85691132151.

It is a cyclic number.

It is not a de Polignac number, because 14315142311 - 210 = 14315141287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14315142319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27146 + ... + 171368.

It is an arithmetic number, because the mean of its divisors is an integer number (3578846448).

Almost surely, 214315142311 is an apocalyptic number.

14315142311 is a deficient number, since it is larger than the sum of its proper divisors (243481).

14315142311 is an equidigital number, since it uses as much as digits as its factorization.

14315142311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 243480.

The product of its digits is 1440, while the sum is 26.

Adding to 14315142311 its reverse (11324151341), we get a palindrome (25639293652).

The spelling of 14315142311 in words is "fourteen billion, three hundred fifteen million, one hundred forty-two thousand, three hundred eleven".

Divisors: 1 99257 144223 14315142311