143188172041 has 4 divisors (see below), whose sum is σ = 143188974612. Its totient is φ = 143187369472.

The previous prime is 143188171993. The next prime is 143188172059. The reversal of 143188172041 is 140271881341.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 140271881341 = 158621 ⋅884321.

It can be written as a sum of positive squares in 2 ways, for example, as 61680206025 + 81507966016 = 248355^2 + 285496^2 .

It is a cyclic number.

It is not a de Polignac number, because 143188172041 - 2²³ = 143179783433 is a prime.

It is a super-2 number, since 2×143188172041² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143188171985 and 143188172003.

It is not an unprimeable number, because it can be changed into a prime (143188173041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285 + ... + 535141.

It is an arithmetic number, because the mean of its divisors is an integer number (35797243653).

Almost surely, 2^143188172041 is an apocalyptic number.

It is an amenable number.

143188172041 is a deficient number, since it is larger than the sum of its proper divisors (802571).

143188172041 is an equidigital number, since it uses as much as digits as its factorization.

143188172041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 802570.

The product of its (nonzero) digits is 43008, while the sum is 40.

The spelling of 143188172041 in words is "one hundred forty-three billion, one hundred eighty-eight million, one hundred seventy-two thousand, forty-one".