1432001113301 has 8 divisors (see below), whose sum is σ = 1563039984384. Its totient is φ = 1301105067520.

The previous prime is 1432001113229. The next prime is 1432001113303. The reversal of 1432001113301 is 1033111002341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1432001113301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1432001113303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35685356 + ... + 35725461.

It is an arithmetic number, because the mean of its divisors is an integer number (195379998048).

Almost surely, 2^{1432001113301} is an apocalyptic number.

1432001113301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1432001113301 is a deficient number, since it is larger than the sum of its proper divisors (131038871083).

1432001113301 is a wasteful number, since it uses less digits than its factorization.

1432001113301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71412651.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1432001113301 its reverse (1033111002341), we get a palindrome (2465112115642).

The spelling of 1432001113301 in words is "one trillion, four hundred thirty-two billion, one million, one hundred thirteen thousand, three hundred one".