Base | Representation |
---|---|
bin | 1101000001100010010001… |
… | …1011010101011000101010 |
3 | 1212200222111122210121120011 |
4 | 3100120210123111120222 |
5 | 3334104411210010442 |
6 | 50242310521522134 |
7 | 3005405513404354 |
oct | 320304433253052 |
9 | 55628448717504 |
10 | 14320032110122 |
11 | 46211008927a2 |
12 | 173339994334a |
13 | 7cb4b0cc0a4b |
14 | 377143c540d4 |
15 | 19c76c06c117 |
hex | d06246d562a |
14320032110122 has 4 divisors (see below), whose sum is σ = 21480048165186. Its totient is φ = 7160016055060.
The previous prime is 14320032110077. The next prime is 14320032110129. The reversal of 14320032110122 is 22101123002341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 14142556114281 + 177475995841 = 3760659^2 + 421279^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14320032110093 and 14320032110102.
It is not an unprimeable number, because it can be changed into a prime (14320032110129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3580008027529 + ... + 3580008027532.
Almost surely, 214320032110122 is an apocalyptic number.
14320032110122 is a deficient number, since it is larger than the sum of its proper divisors (7160016055064).
14320032110122 is an equidigital number, since it uses as much as digits as its factorization.
14320032110122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7160016055063.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 14320032110122 its reverse (22101123002341), we get a palindrome (36421155112463).
The spelling of 14320032110122 in words is "fourteen trillion, three hundred twenty billion, thirty-two million, one hundred ten thousand, one hundred twenty-two".
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