Base | Representation |
---|---|
bin | 1101000001100011000100… |
… | …0100011100000100101100 |
3 | 1212201000001102220111122201 |
4 | 3100120301010130010230 |
5 | 3334110330004241022 |
6 | 50242343535551244 |
7 | 3005414000264254 |
oct | 320306104340454 |
9 | 55630042814581 |
10 | 14320244212012 |
11 | 46211aa591012 |
12 | 173343898b524 |
13 | 7cb515c2451b |
14 | 3771640a6964 |
15 | 19c7809b7127 |
hex | d063111c12c |
14320244212012 has 12 divisors (see below), whose sum is σ = 25303732491856. Its totient is φ = 7090606357200.
The previous prime is 14320244211893. The next prime is 14320244212019. The reversal of 14320244212012 is 21021244202341.
It is not an unprimeable number, because it can be changed into a prime (14320244212019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17378936739 + ... + 17378937562.
Almost surely, 214320244212012 is an apocalyptic number.
It is an amenable number.
14320244212012 is a deficient number, since it is larger than the sum of its proper divisors (10983488279844).
14320244212012 is a wasteful number, since it uses less digits than its factorization.
14320244212012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34757874408 (or 34757874406 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 14320244212012 its reverse (21021244202341), we get a palindrome (35341488414353).
The spelling of 14320244212012 in words is "fourteen trillion, three hundred twenty billion, two hundred forty-four million, two hundred twelve thousand, twelve".
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