14320412114 has 4 divisors (see below), whose sum is σ = 21480618174. Its totient is φ = 7160206056.

The previous prime is 14320412101. The next prime is 14320412131. The reversal of 14320412114 is 41121402341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41121402341 = 78643 ⋅522887.

It can be written as a sum of positive squares in only one way, i.e., 12225061489 + 2095350625 = 110567^2 + 45775^2 .

It is a super-2 number, since 2×14320412114² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14320412114.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3580103027 + ... + 3580103030.

Almost surely, 2^14320412114 is an apocalyptic number.

14320412114 is a deficient number, since it is larger than the sum of its proper divisors (7160206060).

14320412114 is an equidigital number, since it uses as much as digits as its factorization.

14320412114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7160206059.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 14320412114 its reverse (41121402341), we get a palindrome (55441814455).

The spelling of 14320412114 in words is "fourteen billion, three hundred twenty million, four hundred twelve thousand, one hundred fourteen".