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1432104353113 = 71991028072041
BaseRepresentation
bin10100110101110000000…
…100100011110101011001
312001220111210222220122011
4110311300010203311121
5141430422203244423
63013522154225521
7205315611103120
oct24656004436531
95056453886564
101432104353113
11502396632a25
121b1674a252a1
13a507bc52315
144d458314ab7
15273bb8b0b0d
hex14d70123d59

1432104353113 has 8 divisors (see below), whose sum is σ = 1644915267200. Its totient is φ = 1221349583520.

The previous prime is 1432104353107. The next prime is 1432104353117. The reversal of 1432104353113 is 3113534012341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1432104353113 - 25 = 1432104353081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1432104353117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 514034628 + ... + 514037413.

It is an arithmetic number, because the mean of its divisors is an integer number (205614408400).

Almost surely, 21432104353113 is an apocalyptic number.

It is an amenable number.

1432104353113 is a deficient number, since it is larger than the sum of its proper divisors (212810914087).

1432104353113 is a wasteful number, since it uses less digits than its factorization.

1432104353113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1028072247.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 1432104353113 its reverse (3113534012341), we get a palindrome (4545638365454).

The spelling of 1432104353113 in words is "one trillion, four hundred thirty-two billion, one hundred four million, three hundred fifty-three thousand, one hundred thirteen".

Divisors: 1 7 199 1393 1028072041 7196504287 204586336159 1432104353113