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143210535245 = 528642107049
BaseRepresentation
bin1000010101100000000…
…0110101100101001101
3111200122120212222010222
42011120000311211031
54321243344111440
6145442350441125
713226614315241
oct2053000654515
9450576788128
10143210535245
115580a682858
1223908b031a5
1310673a7bbab
146d07b9a421
153ad2a012b5
hex215803594d

143210535245 has 4 divisors (see below), whose sum is σ = 171852642300. Its totient is φ = 114568428192.

The previous prime is 143210535199. The next prime is 143210535257. The reversal of 143210535245 is 542535012341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 84714759364 + 58495775881 = 291058^2 + 241859^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143210535245 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14321053520 + ... + 14321053529.

It is an arithmetic number, because the mean of its divisors is an integer number (42963160575).

Almost surely, 2143210535245 is an apocalyptic number.

It is an amenable number.

143210535245 is a deficient number, since it is larger than the sum of its proper divisors (28642107055).

143210535245 is an equidigital number, since it uses as much as digits as its factorization.

143210535245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28642107054.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 143210535245 its reverse (542535012341), we get a palindrome (685745547586).

The spelling of 143210535245 in words is "one hundred forty-three billion, two hundred ten million, five hundred thirty-five thousand, two hundred forty-five".

Divisors: 1 5 28642107049 143210535245