Base | Representation |
---|---|
bin | 1101000001101000001000… |
… | …0000001111011001110011 |
3 | 1212201010120001221122012110 |
4 | 3100122002000033121303 |
5 | 3334121120112103120 |
6 | 50243130403300403 |
7 | 3005462435663325 |
oct | 320320200173163 |
9 | 55633501848173 |
10 | 14321602066035 |
11 | 4621837003920 |
12 | 173375767a703 |
13 | 7cb6a1337744 |
14 | 377252567615 |
15 | 19c80ecd42e0 |
hex | d068200f673 |
14321602066035 has 128 divisors (see below), whose sum is σ = 26717366550528. Its totient is φ = 6473972736000.
The previous prime is 14321602066027. The next prime is 14321602066097. The reversal of 14321602066035 is 53066020612341.
It is not a de Polignac number, because 14321602066035 - 23 = 14321602066027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14321602065984 and 14321602066002.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 235440925 + ... + 235501745.
It is an arithmetic number, because the mean of its divisors is an integer number (208729426176).
Almost surely, 214321602066035 is an apocalyptic number.
14321602066035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14321602066035 is a deficient number, since it is larger than the sum of its proper divisors (12395764484493).
14321602066035 is a wasteful number, since it uses less digits than its factorization.
14321602066035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61645.
The product of its (nonzero) digits is 155520, while the sum is 39.
Adding to 14321602066035 its reverse (53066020612341), we get a palindrome (67387622678376).
The spelling of 14321602066035 in words is "fourteen trillion, three hundred twenty-one billion, six hundred two million, sixty-six thousand, thirty-five".
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