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14322254011 = 132394609673
BaseRepresentation
bin11010101011010110…
…00100000010111011
31100222010211212222021
431111223010002323
5213312444112021
610325103335311
71014630102412
oct152553040273
940863755867
1014322254011
11608a5a246a
1229385b1537
1314732cc020
1499c200479
1558c58ac41
hex355ac40bb

14322254011 has 8 divisors (see below), whose sum is σ = 15488504640. Its totient is φ = 13165223232.

The previous prime is 14322253999. The next prime is 14322254033. The reversal of 14322254011 is 11045222341.

14322254011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14322254011 - 221 = 14320156859 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14322254081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2301730 + ... + 2307943.

It is an arithmetic number, because the mean of its divisors is an integer number (1936063080).

Almost surely, 214322254011 is an apocalyptic number.

14322254011 is a deficient number, since it is larger than the sum of its proper divisors (1166250629).

14322254011 is a wasteful number, since it uses less digits than its factorization.

14322254011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4609925.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 14322254011 its reverse (11045222341), we get a palindrome (25367476352).

The spelling of 14322254011 in words is "fourteen billion, three hundred twenty-two million, two hundred fifty-four thousand, eleven".

Divisors: 1 13 239 3107 4609673 59925749 1101711847 14322254011