Base | Representation |
---|---|
bin | 11010101011011011… |
… | …00100001101011101 |
3 | 1100222012002012212211 |
4 | 31111231210031131 |
5 | 213313131110140 |
6 | 10325125400421 |
7 | 1014635504143 |
oct | 152555441535 |
9 | 40865065784 |
10 | 14322910045 |
11 | 608aa00344 |
12 | 2938869111 |
13 | 147349b802 |
14 | 99c331593 |
15 | 58c66a2ea |
hex | 355b6435d |
14322910045 has 4 divisors (see below), whose sum is σ = 17187492060. Its totient is φ = 11458328032.
The previous prime is 14322910009. The next prime is 14322910109. The reversal of 14322910045 is 54001922341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4473736996 + 9849173049 = 66886^2 + 99243^2 .
It is a cyclic number.
It is not a de Polignac number, because 14322910045 - 217 = 14322778973 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14322909989 and 14322910016.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1432291000 + ... + 1432291009.
It is an arithmetic number, because the mean of its divisors is an integer number (4296873015).
Almost surely, 214322910045 is an apocalyptic number.
It is an amenable number.
14322910045 is a deficient number, since it is larger than the sum of its proper divisors (2864582015).
14322910045 is an equidigital number, since it uses as much as digits as its factorization.
14322910045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2864582014.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 14322910045 in words is "fourteen billion, three hundred twenty-two million, nine hundred ten thousand, forty-five".
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