Base | Representation |
---|---|
bin | 1000010101100101001… |
… | …0111000110110001111 |
3 | 111200201002100202012111 |
4 | 2011121102320312033 |
5 | 4321314400410211 |
6 | 145444435444451 |
7 | 13230265201240 |
oct | 2053122706617 |
9 | 450632322174 |
10 | 143232044431 |
11 | 55820833a43 |
12 | 23914156727 |
13 | 10678370218 |
14 | 6d0a998cc7 |
15 | 3ad484e421 |
hex | 21594b8d8f |
143232044431 has 8 divisors (see below), whose sum is σ = 163701578880. Its totient is φ = 122764463448.
The previous prime is 143232044339. The next prime is 143232044479. The reversal of 143232044431 is 134440232341.
143232044431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 143232044431 - 29 = 143232043919 is a prime.
It is a super-2 number, since 2×1432320444312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 143232044393 and 143232044402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143232044731) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 327721 + ... + 627586.
It is an arithmetic number, because the mean of its divisors is an integer number (20462697360).
Almost surely, 2143232044431 is an apocalyptic number.
143232044431 is a deficient number, since it is larger than the sum of its proper divisors (20469534449).
143232044431 is an equidigital number, since it uses as much as digits as its factorization.
143232044431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 976733.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 143232044431 its reverse (134440232341), we get a palindrome (277672276772).
The spelling of 143232044431 in words is "one hundred forty-three billion, two hundred thirty-two million, forty-four thousand, four hundred thirty-one".
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