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14323532544449 = 28350613189203
BaseRepresentation
bin1101000001101111010100…
…0100011011100111000001
31212201022112121111002201222
43100123311010123213001
53334134043312410244
650244050124204425
73005561326533302
oct320336504334701
955638477432658
1014323532544449
114622637786927
121733bb6099715
137cb91b27cc6b
14377396ac67a9
1519c8c4512bee
hexd06f511b9c1

14323532544449 has 4 divisors (see below), whose sum is σ = 14374145733936. Its totient is φ = 14272919354964.

The previous prime is 14323532544353. The next prime is 14323532544469. The reversal of 14323532544449 is 94444523532341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14323532544449 - 212 = 14323532540353 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14323532544449.

It is not an unprimeable number, because it can be changed into a prime (14323532544469) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25306594319 + ... + 25306594884.

It is an arithmetic number, because the mean of its divisors is an integer number (3593536433484).

Almost surely, 214323532544449 is an apocalyptic number.

It is an amenable number.

14323532544449 is a deficient number, since it is larger than the sum of its proper divisors (50613189487).

14323532544449 is an equidigital number, since it uses as much as digits as its factorization.

14323532544449 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50613189486.

The product of its digits is 24883200, while the sum is 53.

The spelling of 14323532544449 in words is "fourteen trillion, three hundred twenty-three billion, five hundred thirty-two million, five hundred forty-four thousand, four hundred forty-nine".

Divisors: 1 283 50613189203 14323532544449