Base | Representation |
---|---|
bin | 1101000001110001100010… |
… | …1111100100001111011011 |
3 | 1212201101002022200120020221 |
4 | 3100130120233210033123 |
5 | 3334141310022221210 |
6 | 50244225344300511 |
7 | 3005612215015600 |
oct | 320343057441733 |
9 | 55641068616227 |
10 | 14324131054555 |
11 | 4622914607383 |
12 | 1734142611737 |
13 | 7cb9b527665a |
14 | 3774123a26a7 |
15 | 19c90bd391da |
hex | d0718be43db |
14324131054555 has 24 divisors (see below), whose sum is σ = 20009330259408. Its totient is φ = 9815377900608.
The previous prime is 14324131054549. The next prime is 14324131054567. The reversal of 14324131054555 is 55545013142341.
It is not a de Polignac number, because 14324131054555 - 213 = 14324131046363 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20135964 + ... + 20835193.
It is an arithmetic number, because the mean of its divisors is an integer number (833722094142).
Almost surely, 214324131054555 is an apocalyptic number.
14324131054555 is a deficient number, since it is larger than the sum of its proper divisors (5685199204853).
14324131054555 is a wasteful number, since it uses less digits than its factorization.
14324131054555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40972603 (or 40972596 counting only the distinct ones).
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 14324131054555 its reverse (55545013142341), we get a palindrome (69869144196896).
The spelling of 14324131054555 in words is "fourteen trillion, three hundred twenty-four billion, one hundred thirty-one million, fifty-four thousand, five hundred fifty-five".
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