Base | Representation |
---|---|
bin | 1101000001110001100011… |
… | …1111000111100001010101 |
3 | 1212201101002121100200101120 |
4 | 3100130120333013201111 |
5 | 3334141312043144341 |
6 | 50244230011514153 |
7 | 3005612264455116 |
oct | 320343077074125 |
9 | 55641077320346 |
10 | 14324135131221 |
11 | 4622916941223 |
12 | 1734143a58959 |
13 | 7cb9b6073096 |
14 | 377412b4420d |
15 | 19c90c392066 |
hex | d0718fc7855 |
14324135131221 has 16 divisors (see below), whose sum is σ = 19187263056000. Its totient is φ = 9505316132928.
The previous prime is 14324135131199. The next prime is 14324135131259. The reversal of 14324135131221 is 12213153142341.
14324135131221 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14324135131221 - 222 = 14324130936917 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14324135131121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12033646 + ... + 13170303.
It is an arithmetic number, because the mean of its divisors is an integer number (1199203941000).
Almost surely, 214324135131221 is an apocalyptic number.
It is an amenable number.
14324135131221 is a deficient number, since it is larger than the sum of its proper divisors (4863127924779).
14324135131221 is a wasteful number, since it uses less digits than its factorization.
14324135131221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25204828.
The product of its digits is 17280, while the sum is 33.
Adding to 14324135131221 its reverse (12213153142341), we get a palindrome (26537288273562).
The spelling of 14324135131221 in words is "fourteen trillion, three hundred twenty-four billion, one hundred thirty-five million, one hundred thirty-one thousand, two hundred twenty-one".
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