Base | Representation |
---|---|
bin | 1101000001110001111110… |
… | …0011100101110000001111 |
3 | 1212201101101021202122201120 |
4 | 3100130133203211300033 |
5 | 3334142023302334120 |
6 | 50244244550212023 |
7 | 3005615103402603 |
oct | 320343743456017 |
9 | 55641337678646 |
10 | 14324245355535 |
11 | 46229730863a5 |
12 | 1734174954013 |
13 | 7cba02b5657b |
14 | 377423637503 |
15 | 19c916db6140 |
hex | d071f8e5c0f |
14324245355535 has 16 divisors (see below), whose sum is σ = 23241592465920. Its totient is φ = 7531997557280.
The previous prime is 14324245355527. The next prime is 14324245355557. The reversal of 14324245355535 is 53555354242341.
It is not a de Polignac number, because 14324245355535 - 23 = 14324245355527 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6724996755 + ... + 6724998884.
It is an arithmetic number, because the mean of its divisors is an integer number (1452599529120).
Almost surely, 214324245355535 is an apocalyptic number.
14324245355535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14324245355535 is a deficient number, since it is larger than the sum of its proper divisors (8917347110385).
14324245355535 is a wasteful number, since it uses less digits than its factorization.
14324245355535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13449995718.
The product of its digits is 21600000, while the sum is 51.
Adding to 14324245355535 its reverse (53555354242341), we get a palindrome (67879599597876).
The spelling of 14324245355535 in words is "fourteen trillion, three hundred twenty-four billion, two hundred forty-five million, three hundred fifty-five thousand, five hundred thirty-five".
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