Base | Representation |
---|---|
bin | 1101000001110010010000… |
… | …1001001110101011000111 |
3 | 1212201101120122121102200010 |
4 | 3100130210021032223013 |
5 | 3334142203004100320 |
6 | 50244300340121303 |
7 | 3005620026602052 |
oct | 320344411165307 |
9 | 55641518542603 |
10 | 14324322331335 |
11 | 4622a02581465 |
12 | 1734196696233 |
13 | 7cba15a98293 |
14 | 37742d953a99 |
15 | 19c91da1dae0 |
hex | d072424eac7 |
14324322331335 has 16 divisors (see below), whose sum is σ = 22920468120576. Its totient is φ = 7639121113248.
The previous prime is 14324322331309. The next prime is 14324322331357. The reversal of 14324322331335 is 53313322342341.
It is not a de Polignac number, because 14324322331335 - 26 = 14324322331271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14324322331293 and 14324322331302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32112579 + ... + 32555588.
It is an arithmetic number, because the mean of its divisors is an integer number (1432529257536).
Almost surely, 214324322331335 is an apocalyptic number.
14324322331335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14324322331335 is a deficient number, since it is larger than the sum of its proper divisors (8596145789241).
14324322331335 is a wasteful number, since it uses less digits than its factorization.
14324322331335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64682942.
The product of its digits is 466560, while the sum is 39.
Adding to 14324322331335 its reverse (53313322342341), we get a palindrome (67637644673676).
The spelling of 14324322331335 in words is "fourteen trillion, three hundred twenty-four billion, three hundred twenty-two million, three hundred thirty-one thousand, three hundred thirty-five".
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