Base | Representation |
---|---|
bin | 1101000001110101100010… |
… | …1101011100101011010111 |
3 | 1212201110212010002002110011 |
4 | 3100131120231130223113 |
5 | 3334201004241203421 |
6 | 50244524042341051 |
7 | 3005650625654431 |
oct | 320353055345327 |
9 | 55643763062404 |
10 | 14325204241111 |
11 | 4623315378315 |
12 | 17343a1aba787 |
13 | 7cbb266c989a |
14 | 3774b4b21651 |
15 | 19c9711754e1 |
hex | d0758b5cad7 |
14325204241111 has 4 divisors (see below), whose sum is σ = 14658348525832. Its totient is φ = 13992059956392.
The previous prime is 14325204241099. The next prime is 14325204241147. The reversal of 14325204241111 is 11114240252341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14325204241111 - 229 = 14324667370199 is a prime.
It is a super-2 number, since 2×143252042411112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14325204281111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166572142296 + ... + 166572142381.
It is an arithmetic number, because the mean of its divisors is an integer number (3664587131458).
Almost surely, 214325204241111 is an apocalyptic number.
14325204241111 is a deficient number, since it is larger than the sum of its proper divisors (333144284721).
14325204241111 is an equidigital number, since it uses as much as digits as its factorization.
14325204241111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 333144284720.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 14325204241111 its reverse (11114240252341), we get a palindrome (25439444493452).
The spelling of 14325204241111 in words is "fourteen trillion, three hundred twenty-five billion, two hundred four million, two hundred forty-one thousand, one hundred eleven".
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