Base | Representation |
---|---|
bin | 1101000001110101101011… |
… | …1111100001101000110011 |
3 | 1212201110221210010121001000 |
4 | 3100131122333201220303 |
5 | 3334201044042100301 |
6 | 50244531531213043 |
7 | 3005651602314012 |
oct | 320353277415063 |
9 | 55643853117030 |
10 | 14325242534451 |
11 | 4623334a52702 |
12 | 17343b28a7183 |
13 | 7cbb31616674 |
14 | 3774b9c4ca79 |
15 | 19c9746db786 |
hex | d075afe1a33 |
14325242534451 has 32 divisors (see below), whose sum is σ = 21564424224000. Its totient is φ = 9397548526464.
The previous prime is 14325242534441. The next prime is 14325242534453. The reversal of 14325242534451 is 15443524252341.
14325242534451 is a `hidden beast` number, since 1 + 4 + 3 + 25 + 2 + 42 + 534 + 4 + 51 = 666.
It is not a de Polignac number, because 14325242534451 - 25 = 14325242534419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14325242534397 and 14325242534406.
It is not an unprimeable number, because it can be changed into a prime (14325242534453) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16465341 + ... + 17313518.
It is an arithmetic number, because the mean of its divisors is an integer number (673888257000).
Almost surely, 214325242534451 is an apocalyptic number.
14325242534451 is a deficient number, since it is larger than the sum of its proper divisors (7239181689549).
14325242534451 is a wasteful number, since it uses less digits than its factorization.
14325242534451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33779120 (or 33779114 counting only the distinct ones).
The product of its digits is 2304000, while the sum is 45.
Adding to 14325242534451 its reverse (15443524252341), we get a palindrome (29768766786792).
The spelling of 14325242534451 in words is "fourteen trillion, three hundred twenty-five billion, two hundred forty-two million, five hundred thirty-four thousand, four hundred fifty-one".
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