14325255252341 has 4 divisors (see below), whose sum is σ = 15627551184384. Its totient is φ = 13022959320300.

The previous prime is 14325255252289. The next prime is 14325255252359.

14325255252341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14325255252341 - 2²² = 14325251058037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14325255252292 and 14325255252301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14325255252361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 651147966005 + ... + 651147966026.

It is an arithmetic number, because the mean of its divisors is an integer number (3906887796096).

Almost surely, 2^{14325255252341} is an apocalyptic number.

14325255252341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14325255252341 is a deficient number, since it is larger than the sum of its proper divisors (1302295932043).

14325255252341 is a wasteful number, since it uses less digits than its factorization.

14325255252341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1302295932042.

The product of its digits is 1440000, while the sum is 44.

It can be divided in two parts, 1432525 and 5252341, that added together give a palindrome (6684866).

The spelling of 14325255252341 in words is "fourteen trillion, three hundred twenty-five billion, two hundred fifty-five million, two hundred fifty-two thousand, three hundred forty-one".