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14325341011 = 127811120831
BaseRepresentation
bin11010101011101101…
…10101101101010011
31100222100122201112121
431111312311231103
5213314241403021
610325253435111
71014665250412
oct152566655523
940870581477
1014325341011
116091310803
12293963ba97
131473b40157
1499c7a5479
1558c99a741
hex355db5b53

14325341011 has 4 divisors (see below), whose sum is σ = 14326474624. Its totient is φ = 14324207400.

The previous prime is 14325341003. The next prime is 14325341053. The reversal of 14325341011 is 11014352341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11014352341 = 17836177427.

It is a cyclic number.

It is not a de Polignac number, because 14325341011 - 23 = 14325341003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14325341071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 547635 + ... + 573196.

It is an arithmetic number, because the mean of its divisors is an integer number (3581618656).

Almost surely, 214325341011 is an apocalyptic number.

14325341011 is a deficient number, since it is larger than the sum of its proper divisors (1133613).

14325341011 is a wasteful number, since it uses less digits than its factorization.

14325341011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1133612.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 14325341011 its reverse (11014352341), we get a palindrome (25339693352).

The spelling of 14325341011 in words is "fourteen billion, three hundred twenty-five million, three hundred forty-one thousand, eleven".

Divisors: 1 12781 1120831 14325341011