14325405235 has 4 divisors (see below), whose sum is σ = 17190486288. Its totient is φ = 11460324184.

The previous prime is 14325405233. The next prime is 14325405253. The reversal of 14325405235 is 53250452341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14325405235 - 2¹ = 14325405233 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14325405235.

It is not an unprimeable number, because it can be changed into a prime (14325405233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1432540519 + ... + 1432540528.

It is an arithmetic number, because the mean of its divisors is an integer number (4297621572).

Almost surely, 2^14325405235 is an apocalyptic number.

14325405235 is a deficient number, since it is larger than the sum of its proper divisors (2865081053).

14325405235 is an equidigital number, since it uses as much as digits as its factorization.

14325405235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2865081052.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 14325405235 its reverse (53250452341), we get a palindrome (67575857576).

The spelling of 14325405235 in words is "fourteen billion, three hundred twenty-five million, four hundred five thousand, two hundred thirty-five".