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143260113 = 353901007
BaseRepresentation
bin10001000100111…
…11100111010001
3100222120100221010
420202133213101
5243133310423
622114321133
73356455653
oct1042374721
9328510833
10143260113
1173959497
123bb891a9
13238ac1c9
14150526d3
15c89c693
hex889f9d1

143260113 has 8 divisors (see below), whose sum is σ = 194617728. Its totient is φ = 93704624.

The previous prime is 143260111. The next prime is 143260121. The reversal of 143260113 is 311062341.

143260113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143260113 - 21 = 143260111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 143260113.

It is not an unprimeable number, because it can be changed into a prime (143260111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 450345 + ... + 450662.

It is an arithmetic number, because the mean of its divisors is an integer number (24327216).

Almost surely, 2143260113 is an apocalyptic number.

It is an amenable number.

143260113 is a deficient number, since it is larger than the sum of its proper divisors (51357615).

143260113 is an equidigital number, since it uses as much as digits as its factorization.

143260113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 901063.

The product of its (nonzero) digits is 432, while the sum is 21.

The square root of 143260113 is about 11969.1316727656. The cubic root of 143260113 is about 523.2490274444.

The spelling of 143260113 in words is "one hundred forty-three million, two hundred sixty thousand, one hundred thirteen".

Divisors: 1 3 53 159 901007 2703021 47753371 143260113