Base | Representation |
---|---|
bin | 11010101011110010… |
… | …11101111011100011 |
3 | 1100222101221201201121 |
4 | 31111321131323203 |
5 | 213314430430201 |
6 | 10325320313111 |
7 | 1015004150314 |
oct | 152571357343 |
9 | 40871851647 |
10 | 14326030051 |
11 | 6091741463 |
12 | 2939912797 |
13 | 1474021978 |
14 | 99c90460b |
15 | 58ca849a1 |
hex | 355e5dee3 |
14326030051 has 16 divisors (see below), whose sum is σ = 14701113504. Its totient is φ = 13956655104.
The previous prime is 14326030049. The next prime is 14326030057. The reversal of 14326030051 is 15003062341.
It is a cyclic number.
It is not a de Polignac number, because 14326030051 - 21 = 14326030049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14326029998 and 14326030025.
It is not an unprimeable number, because it can be changed into a prime (14326030057) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2529615 + ... + 2535271.
It is an arithmetic number, because the mean of its divisors is an integer number (918819594).
Almost surely, 214326030051 is an apocalyptic number.
14326030051 is a deficient number, since it is larger than the sum of its proper divisors (375083453).
14326030051 is a wasteful number, since it uses less digits than its factorization.
14326030051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6150.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 14326030051 its reverse (15003062341), we get a palindrome (29329092392).
The spelling of 14326030051 in words is "fourteen billion, three hundred twenty-six million, thirty thousand, fifty-one".
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