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14326030111 = 37387190003
BaseRepresentation
bin11010101011110010…
…11101111100011111
31100222101221201210211
431111321131330133
5213314430430421
610325320313251
71015004150431
oct152571357437
940871851724
1014326030111
116091741508
122939912827
1314740219c3
1499c904651
1558ca849e1
hex355e5df1f

14326030111 has 4 divisors (see below), whose sum is σ = 14713220152. Its totient is φ = 13938840072.

The previous prime is 14326030109. The next prime is 14326030123. The reversal of 14326030111 is 11103062341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14326030111 - 21 = 14326030109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14326040111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193594965 + ... + 193595038.

It is an arithmetic number, because the mean of its divisors is an integer number (3678305038).

Almost surely, 214326030111 is an apocalyptic number.

14326030111 is a deficient number, since it is larger than the sum of its proper divisors (387190041).

14326030111 is an equidigital number, since it uses as much as digits as its factorization.

14326030111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 387190040.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 14326030111 its reverse (11103062341), we get a palindrome (25429092452).

It can be divided in two parts, 143260 and 30111, that added together give a palindrome (173371).

The spelling of 14326030111 in words is "fourteen billion, three hundred twenty-six million, thirty thousand, one hundred eleven".

Divisors: 1 37 387190003 14326030111