Base | Representation |
---|---|
bin | 1000010101110111110… |
… | …0010001000000000011 |
3 | 111200220112001022022122 |
4 | 2011131330101000003 |
5 | 4321444330001011 |
6 | 145500302354455 |
7 | 13232232621314 |
oct | 2053574210003 |
9 | 450815038278 |
10 | 143310000131 |
11 | 55860839241 |
12 | 2393628ba2b |
13 | 1068b565c5c |
14 | 6d1708c60b |
15 | 3adb5ec3db |
hex | 215df11003 |
143310000131 has 4 divisors (see below), whose sum is σ = 143322900000. Its totient is φ = 143297100264.
The previous prime is 143310000121. The next prime is 143310000181. The reversal of 143310000131 is 131000013341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143310000131 is a prime.
It is a super-2 number, since 2×1433100001312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143310000101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6433256 + ... + 6455493.
It is an arithmetic number, because the mean of its divisors is an integer number (35830725000).
Almost surely, 2143310000131 is an apocalyptic number.
143310000131 is a deficient number, since it is larger than the sum of its proper divisors (12899869).
143310000131 is a wasteful number, since it uses less digits than its factorization.
143310000131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12899868.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 143310000131 its reverse (131000013341), we get a palindrome (274310013472).
The spelling of 143310000131 in words is "one hundred forty-three billion, three hundred ten million, one hundred thirty-one", and thus it is an aban number.
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